4x^2-56x-75=0

Solution for 4x^2-56x-75=0 equation:

4x^2-56x-75=0

a = 4; b = -56; c = -75;
Δ = b2-4ac
Δ = -562-4·4·(-75)
Δ = 4336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4336}=\sqrt{16*271}=\sqrt{16}*\sqrt{271}=4\sqrt{271}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-4\sqrt{271}}{2*4}=\frac{56-4\sqrt{271}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+4\sqrt{271}}{2*4}=\frac{56+4\sqrt{271}}{8}
$